Pattern 250

#include <iostream.h>


int main()
{
  int n = 5;
  

  for(int i = 1; i <= n; i++)
  {
    for(int j = 1; j < i * 2; j++)
    {
      if (j < i)
      {
        cout<<(n + j - i)<<" ";
      }
      else if (j == i)
      {
        cout<<"0 ";
      }
      else
      {
       cout<<(n - j + i)<<" ";
      }
    }
    cout<<endl;
  }
  return 0;
}

class PatternProg
{
	public static void main(String args[])
	{
	  int n = 5;


	  for (int i = 1; i <= n; i++)
	  {
		for (int j = 1; j < i * 2; j++)
		{
		  if (j < i)
		  {
			System.out.print((n + j - i)+" ");
		  }
		  else if (j == i)
		  {
			System.out.print("0 ");
		  }
		  else
		  {
		   System.out.print((n - j + i)+" ");
		  }
		}
		System.out.println();
	  }
	  
	}
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;


    for (int i = 1; i <= n; i++)
    {
      for (int j = 1; j < i * 2; j++)
      {
        if (j < i)
        {
          Console.Write((n + j - i) + " ");
        }
        else if (j == i)
        {
          Console.Write("0 ");
        }
        else
        {
          Console.Write((n - j + i) + " ");
        }
      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

n = 5

for x in range(1, n + 1):
  for y in range(1, x * 2):
    if y < x:
       print(str(n + y - x) + " ", end="")
    elif y == x:
       print("0 ", end="")
    else:
       print(str(n - y + x) + " ", end="")
  print()