Pattern 262

#include <stdio.h>
int main()
{
  int i,j;
  int n=5;

  for(i=1; i<=n; i++)
  {
    for(j=1; j<=i; j++)
    {
      if(j%2==0)
        printf("*");
      else
        printf("#");
    }
    printf("\n");
  }
  return 0;
}

#include <iostream.h>
int main()
{
	
	int n=5;
	
	for(int i =1;i<=n;i++)
    {
     for(int j =1;j<=i;j++)
      {
       if(j%2==0)
	   cout<<"*";           
	   else
	   cout<<"#";           
      }
      cout<<endl;           
    }
	return 0;
}

class PatternProg
{
	public static void main(String args[])
	{

		int n = 5;

		for (int i = 1;i <= n;i++)
		{
		 for (int j = 1;j <= i;j++)
		 {
		   if (j % 2 == 0)
		   {
		   System.out.print("*");
		   }
		   else
		   {
		   System.out.print("#");
		   }
		 }
		  System.out.println();
		}
		
	}
}

using System;

class PatternProg
{
  public static void Main()
  {

    int n = 5;

    for (int i = 1; i <= n; i++)
    {
      for (int j = 1; j <= i; j++)
      {
        if (j % 2 == 0)
        {
          Console.Write("*");
        }
        else
        {
          Console.Write("#");
        }
      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

n = 5

for x in range(1, n + 1):
  for y in range(1, x + 1):
    if y % 2 == 0:
       print("*", end="")
    else:
       print("#", end="")
  print()