Pattern 395

#include <iostream.h>

int main()
{
 int n = 9; // size

 int px = n/2+1; // print controls


 int i,j; // loop var

 for(i = 1; i <= n; i++)
 {
  for(j = 1; j <= n; j++)
  {
   if (j == px || j == n-px+1 )
   {
    cout<<char(px+64); // 1+64=65 = 'A'
   }
   else
   {
    cout<<" ";
   }
  }
  
  if(i <= n/2)
  px--;
  else
  px++;
  
  cout<<endl;
 }

return 0;
}

class PatternProg
{
    public static void main(String args[])
    {
        int n = 9; // size

        int px = n / 2 + 1; // print controls

        for (int i = 1; i <= n; i++)
        {
            for (int j = 1; j <= n; j++)
            {
                if (j == px || j == n - px + 1)
                {
                    System.out.print((char)(px + 64));
                }
                else
                {
                    System.out.print(" ");
                }
            }

            if (i <= n / 2)
                px--;
            else
                px++;

            System.out.println();
        }

    }
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 9; // size
    int px = n / 2 + 1; // print controls

    for (int i = 1; i <= n; i++)
    {
      for (int j = 1; j <= n; j++)
      {
        if (j == px || j == n - px + 1)
        {
          Console.Write((char)(px + 64));
        }
        else
        {
          Console.Write(" ");
        }
      }

      if (i <= n / 2)
      {
        px--;
      }
      else
      {
        px++;
      }

      Console.WriteLine();
    }
    Console.ReadKey(true);
  }
}

n = 9  # size
px = n // 2 + 1
for x in range(1, n + 1):
    for y in range(1, n + 1):
        if (y == px or y == n - px + 1):
            print(chr(px + 64), end="")  # 1
        else:
            print(" ", end="")
    if (x <= n / 2):
        px -= 1
    else:
        px += 1
    print()

"""
 5+64>> 69 >> ASCII of 'E'
"""