Pattern 8

 #include<stdio.h> 
 int main()
 {
   int n = 5;
   int i,j;
   int x = 2;
   for(i = 1; i <= n; i++)
   {
     for (j = 1; j <= n; j++)
     {
       printf("%2d ", x);
       x += 2;
     }
     printf("\n");
   }
   return 0;
 }

 #include<iostream.h> 
 int main()
 {
   int n = 5;
   int x = 2;
   for(int i = 1; i <= n; i++)
   {
     for(int j = 1; j <= n; j++)
     {
       cout<<x<<" ";
       x += 2;
     }
     cout<<endl;
   }
   return 0;
 }

 class PatternProg
 {
   public static void main(String args[])
   {
     int n = 5;
     
     int x = 2;
     
     for (int i = 1; i <= n; i++)
     {
       for (int j = 1; j <= n; j++)
       {
         System.out.printf("%2d ",x);
         x += 2;
       }
       System.out.println();
     }
 }
 }

 using System;
 class PatternProg
 {
   public static void Main()
   {
     int n = 5;
     
     int x = 2;
     
     for (int i = 1; i <= n; i++)
     {
       for (int j = 1; j <= n; j++)
       {
         Console.Write("{0,2:D} ", x);
         x += 2;
       }
       Console.WriteLine();
     }
     Console.ReadKey(true);
   }
 }

 n = 5
 p = 2

 for x in range(1, n + 1):
     for y in range(1, n + 1):
         print("{:2d} ".format(p), end="")
         p += 2

     print()