Pattern 45

#include <stdio.h>

int main()
{
  int n = 5, x = 1;
  int i,j;

  for(i = n; i >= 1; i--)
  {
    for (j = n; j >= i; j--)
    {
      printf("%2d ", x);
      x+=2;
    }
    printf("\n");
  }
  return 0;
}

#include <iostream.h>

int main()
{
  int n = 5, x = 1;
  

  for(int i = n; i >= 1; i--)
  {
    for(int j = n; j >= i; j--)
    {
      cout<<x<<" ";
      x+=2;
    }
    cout<<endl;
  }
  return 0;
}

  class PatternProg
  {
	public static void main(String args[])
	{
	  int n = 5;
	  int x = 1;


	  for (int i = n; i >= 1; i--)
	  {
		for (int j = n; j >= i; j--)
		{
		  System.out.printf("%2d ",x);
		  x += 2;
		}
		System.out.println();
	  }
	  
	}
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;
    int x = 1;


    for (int i = n; i >= 1; i--)
    {
      for (int j = n; j >= i; j--)
      {
        Console.Write("{0,2:D} ", x);
        x += 2;
      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

p = 1

for x in range(5, 0, -1):
    for y in range(6, x, -1):
        print("{:2d} ".format(p), end="")
        p += 2
    print()