Pattern 195

#include <stdio.h>

int main()
{
  int n = 5;
  int i,j;
  int x = 1, y = n * 2;

  for(i = 1; i <= n; i++)
  {
    for (j = 1; j <= n; j++)
    {
      if (i <= n / 2 + 1)
      {
        printf("%2d ", x);
      }
      else
      {
        printf("%2d ", y);
      }
    }
    x += 2;
    y -= 2;
    printf("\n");
  }
  return 0;
}

#include <iostream.h>

int main()
{
  int n = 5;
  
  int x = 1, y = n * 2;

  for(int i = 1; i <= n; i++)
  {
    for(int j = 1; j <= n; j++)
    {
      if (i <= n / 2 + 1)
      {
        cout<<x<<" ";
      }
      else
      {
        cout<<y<<" ";
      }
    }
    x += 2;
    y -= 2;
    cout<<endl;
  }
  return 0;
}

class PatternProg
{
	public static void main(String args[])
	{
	  int n = 5;

	  int x = 1;
	  int y = n * 2;

	  for (int i = 1; i <= n; i++)
	  {
		for (int j = 1; j <= n; j++)
		{
		  if (i <= n / 2 + 1)
		  {
			System.out.print(x+" ");
		  }
		  else
		  {
		    System.out.print(y+" ");
		  }
		}
		x += 2;
		y -= 2;
		System.out.println();
	  }
	  
	}
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;

    int x = 1;
    int y = n * 2;

    for (int i = 1; i <= n; i++)
    {
      for (int j = 1; j <= n; j++)
      {
        if (i <= n / 2 + 1)
        {
          Console.Write(x + " ");
        }
        else
        {
          Console.Write(y + " ");
        }
      }
      x += 2;
      y -= 2;
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

n = 5
d = 1
e = n * 2

for x in range(1, n + 1):
    for y in range(1, n + 1):
        if x <= n // 2 + 1:
            print(d, end=" ");
        else:
            print(e, end=" ");

    d += 2
    e -= 2
    print()