Pattern 254

#include <iostream.h>

int main()
{
  int n = 5;
  

  int x = 1,k;

  for(int i = 1; i <= n; i++)
  {
    k = x + i;
    for(int j = 1; j <= i; j++)
    {
      if (i % 2 == 1)
      {
        cout<<(x + j - 1)<<" ";
      }
      else
      {
        cout<<(k - j)<<" ";
      }
      
      if (j != i)
      {
        cout<<"# ";
      }
    }
    x = x + i;
    cout<<endl;
  }
  return 0;
}

class PatternProg
{
	public static void main(String args[])
	{
	  int n = 5;


	  int x = 1,k;

	  for (int i = 1; i <= n; i++)
	  {
		k = x + i;
		for (int j = 1; j <= i; j++)
		{
		  if (i % 2 == 1)
		  {
			System.out.printf("%2d ",(x + j - 1));
		  }
		  else
		  {
			System.out.printf("%2d ",(k - j));
		  }

		  if (j != i)
		  {
			System.out.print("# ");
		  }
		}
		x = x + i;
		System.out.println();
	  }
	  
	}
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;


    int x = 1, k;

    for (int i = 1; i <= n; i++)
    {
      k = x + i;
      for (int j = 1; j <= i; j++)
      {
        if (i % 2 == 1)
        {
          Console.Write("{0,2:D} ", (x + j - 1));
        }
        else
        {
          Console.Write("{0,2:D} ", (k - j));
        }

        if (j != i)
        {
          Console.Write("# ");
        }
      }
      x = x + i;
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

n = 5

d = 1

for x in range(1, n + 1):
  k = d + x
  for y in range(1, x + 1):
      if x % 2 == 1:
         print("{:2d} ".format(d + y - 1), end="")
      else:
         print("{:2d} ".format(k - y), end="")

      if y != x:
         print("# ", end="")

  d = d + x
  print()