Pattern 256

#include <stdio.h>

int main()
{
  int n = 5;
  int i,j;

  for(i = n; i >= 1; i--)
  {
    for (j = 1; j <= i; j++)
    {
      if (i % 2 == 0)
      {
        printf("%2d ", j);
      }
      else
      {
        printf("%2d ", n - j + 1);
      }
    }
    printf("\n");
  }
  return 0;
}

#include <iostream.h>

int main()
{
  int n = 5;
  

  for(int i = n; i >= 1; i--)
  {
    for(int j = 1; j <= i; j++)
    {
      if (i % 2 == 0)
      {
        cout<<j<<" ";
      }
      else
      {
        cout<<(n - j + 1)<<" ";
      }
    }
    cout<<endl;
  }
  return 0;
}

class PatternProg
{
	public static void main(String args[])
	{
	  int n = 5;


	  for (int i = n; i >= 1; i--)
	  {
		for (int j = 1; j <= i; j++)
		{
		  if (i % 2 == 0)
		  {
			System.out.print(j+" ");
		  }
		  else
		  {
			System.out.print((n - j + 1)+" ");
		  }
		}
		System.out.println();
	  }
	  
	}
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;


    for (int i = n; i >= 1; i--)
    {
      for (int j = 1; j <= i; j++)
      {
        if (i % 2 == 0)
        {
          Console.Write(j + " ");
        }
        else
        {
          Console.Write((n - j + 1) + " ");
        }
      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

n = 5

for x in range(n, 0, -1):
  for y in range(1, x + 1):
    if x % 2 == 0:
       print(y, end=" ")
    else:
       print(str(n - y + 1)+ " ",end="")
  print()