Pattern 260

#include <stdio.h>

int main()
{
  int n = 5;
  int i,j;
  for(i = 1; i <= n; i++)
  {
    for(j = 1; j <= 2 * (n - i + 1); j++)
    {
      if (j <= n - i + 1)
        printf("%c", 64 + j);
      else
        printf("%c", 65 + (2 * (n - i + 1) - j));
    }
    printf("\n");
  }
  return 0;
}

#include <iostream.h>

int main()
{
  int n = 5;
  
  for(int i = 1; i <= n; i++)
  {
    for(int j = 1; j <= 2 * (n - i + 1); j++)
    {
      if (j <= n - i + 1)
        cout<<(char)(64 + j);
      else
        cout<<(char)(65 + (2 * (n - i + 1) - j));
    }
    cout<<endl;
  }
  return 0;
}

class PatternProg
{
	public static void main(String args[])
	{
	  int n = 5;

	  for (int i = 1; i <= n; i++)
	  {
		for (int j = 1; j <= 2 * (n - i + 1); j++)
		{
		  if (j <= n - i + 1)
		  {
			System.out.print((char)(64 + j));
		  }
		  else
		  {
			System.out.print((char)(65 + (2 * (n - i + 1) - j)));
		  }
		}
		System.out.println();
	  }
	  
	}
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;

    for (int i = 1; i <= n; i++)
    {
      for (int j = 1; j <= 2 * (n - i + 1); j++)
      {
        if (j <= n - i + 1)
        {
          Console.Write((char)(64 + j));
        }
        else
        {
          Console.Write((char)(65 + (2 * (n - i + 1) - j)));
        }
      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

n = 5

for x in range(1, n + 1):
  for y in range(1, 2 * (n - x + 1) + 1):
    if y <= n - x + 1:
       print(chr(64 + y), end="")
    else:
       print(chr(65 + (2 * (n - x + 1) - y)), end="")
  print()