Pattern 33

#include <stdio.h>

int main()
{
  int n = 5;
  int i,j;
  int x;
  for(i = 1; i <= n; i++)
  {
    x = n - i ;
    for(j = 1; j <= n; j++)
    {
      printf("%c ", x + 65);
      x = x + n;
    }
    printf("\n");
  }
  return 0;
}

#include <iostream.h>

int main()
{
  int n = 5;
  
  int x;
  for(int i = 1; i <= n; i++)
  {
    x = n - i ;
    for(int j = 1; j <= n; j++)
    {
      cout<<(char)(x + 65)<<" ";
      x = x + n;
    }
    cout<<endl;
  }
  return 0;
}

  class PatternProg
  {
  public static void main(String args[])
  {
    int n = 5;

    int x;
    for (int i = 1; i <= n; i++)
    {
      x = n - i;
      for (int j = 1; j <= n; j++)
      {
        System.out.print((char)(x + 65)+" ");
        x = x + n;
      }
      System.out.println();
    }

  }
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;

    int x;
    for (int i = 1; i <= n; i++)
    {
      x = n - i;
      for (int j = 1; j <= n; j++)
      {
        Console.Write((char)(x + 65) + " ");
        x = x + n;
      }
      Console.WriteLine();
    }
    Console.ReadKey(true);
  }
}

n = 5

for x in range(1, n + 1):
  p = n - x;
  for y in range(1, n + 1):
    print(chr(p + 65) + " ", end="")
    p = p + n
  print()