#include <stdio.h>
int main()
{
int n = 5;
int i,j;
int x=n,y,t;
for(i = n; i >= 1; i--)
{
t = x;
y = i + 1;
for (j = n; j >= i; j--)
{
printf("%2d ", t);
t = t - y;
y++;
}
x = x + i - 1;
printf("\n");
}
return 0;
}
#include <iostream.h>
int main()
{
int n = 5;
int x=n,y,t;
for(int i = n; i >= 1; i--)
{
t = x;
y = i + 1;
for(int j = n; j >= i; j--)
{
cout<<t<<" ";
t = t - y;
y++;
}
x = x + i - 1;
cout<<endl;
}
return 0;
}
class PatternProg
{
public static void main(String args[])
{
int n = 5;
int x = n;
int y;
int t;
for (int i = n; i >= 1; i--)
{
t = x;
y = i + 1;
for (int j = n; j >= i; j--)
{
System.out.printf("%2d ",t);
t = t - y;
y++;
}
x = x + i - 1;
System.out.println();
}
}
}
using System;
class PatternProg
{
public static void Main()
{
int n = 5;
int x = n;
int y;
int t;
for (int i = n; i >= 1; i--)
{
t = x;
y = i + 1;
for (int j = n; j >= i; j--)
{
Console.Write("{0,2:D} ", t);
t = t - y;
y++;
}
x = x + i - 1;
Console.WriteLine();
}
Console.ReadKey(true);
}
}
n = 5
d = n
for x in range(n, 0, -1):
t = d
e = x + 1
for y in range(n, x - 1, -1):
print("{:2d} ".format(t), end="")
t = t - e
e += 1
d = d + x - 1
print()