Pattern 94

#include <stdio.h>

int main()
{
  int n = 5;
  int i,j;
  char ch = 'A';

  for(i = 1; i <= n; i++)
  {
    for(j = 1; j <= i; j++)
    {
      printf("%c", ch);

      if(ch<'Z')
        ch++;
      else
        ch='A';

      /* reset char*/
    }
    printf("\n");
  }
  return 0;
}

#include <iostream.h>

int main()
{
  int n = 5;
  
  char ch = 'A';

  for(int i = 1; i <= n; i++)
  {
    for(int j = 1; j <= i; j++)
    {
      cout<<ch<<" ";

      if(ch<'Z')
         ch++;
      else
         ch='A';

     /* reset char*/
    }
    cout<<endl;
  }
  return 0;
}

class PatternProg
{
	public static void main(String args[])
	{
	  int n = 5;

	  char ch = 'A';

	  for (int i = 1; i <= n; i++)
	  {
		for (int j = 1; j <= i; j++)
		{
		  System.out.print(ch+" ");
		  
		  if (ch < 'Z')
		  {
			 ch++;
		  }
		  else
		  {
			 ch = (char)'A';
		  }

		 /* reset char*/
		}
		System.out.println();
	  }
	  
	}
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;

    char ch = 'A';

    for (int i = 1; i <= n; i++)
    {
      for (int j = 1; j <= i; j++)
      {
        Console.Write(ch + " ");

        if (ch < 'Z')
        {
          ch++;
        }
        else
        {
          ch = 'A';
        }

        /* reset char*/
      }
      Console.WriteLine();
    }
    Console.ReadKey(true);
  }
}

n = 5
ch = 0

for x in range(1, n + 1):
    for y in range(1, x + 1):
        print(chr(ch + 65)+" ", end="")
        if ch < 26:
            ch += 1
        else:
            ch = 0
    print()