Pattern 152

#include <iostream.h>

int main()
{
  int n = 5;
  

  for(int i = 1; i <= n; i++)
  {
    for(int j = 1; j <= n * 2; j++)
    {
      if (j >= n - i + 1 && j <= n)
      {
        cout<<j<<" ";
      }
      else if (j > n && j + 1 <= n + i)
      {
        cout<<(n * 2 - j)<<" ";
      }
      else
      {
        cout<<"  "; // 2ws
      }
    }
    cout<<endl;
  }
  return 0;
}

class PatternProg
{
	public static void main(String args[])
	{
	  int n = 5;


	  for (int i = 1; i <= n; i++)
	  {
		for (int j = 1; j <= n * 2; j++)
		{
		  if (j >= n - i + 1 && j <= n)
		  {
			System.out.print(j+" ");
		  }
		  else if (j > n && j + 1 <= n + i)
		  {
			System.out.print((n * 2 - j)+" ");
	  }
		  else
		  {
			System.out.print("  "); // 2ws
		  }
		}
		System.out.println();
	  }
	  
	}
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;


    for (int i = 1; i <= n; i++)
    {
      for (int j = 1; j <= n * 2; j++)
      {
        if (j >= n - i + 1 && j <= n)
        {
          Console.Write(j + " ");
        }
        else if (j > n && j + 1 <= n + i)
        {
          Console.Write((n * 2 - j) + " ");
        }
        else
        {
          Console.Write("  "); // 2ws
        }
      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

n = 5

for x in range(1, n + 1):
  for y in range(1, (n * 2) + 1):
    if y >= n - x + 1 and y <= n :
       print(y, end=" ")
    elif y > n and y + 1 <= n + x:
       print(str(n * 2 - y)+" ", end=" ")
    else:
       print("  ", end="")  # 2ws
  print()