Pattern 210

#include <stdio.h>

int main()
{
  int n = 5;
  int i,j;

  for(i = n-1; i >= 0; i--)
  {
    for (j = 0; j <= n-1; j++)
    {
      printf("%2d ", abs(i - j));
    }
    printf("\n");
  }
  return 0;
}

#include <iostream.h>

int main()
{
  int n = 5;
  

  for(int i = n-1; i >= 0; i--)
  {
    for(int j = 0; j <= n-1; j++)
    {
      cout<<abs(i-j)<<" ";
    }
    cout<<endl;
  }
  return 0;
}

class PatternProg
{
	public static void main(String args[])
	{
	  int n = 5;


	  for (int i = n - 1; i >= 0; i--)
	  {
		for (int j = 0; j <= n - 1; j++)
		{
		  System.out.print(Math.abs(i - j)+" ");
		}
		System.out.println();
	  }
	  
	}
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;


    for (int i = n - 1; i >= 0; i--)
    {
      for (int j = 0; j <= n - 1; j++)
      {
        Console.Write(Math.Abs(i - j) + " ");
      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

n = 5

for x in range(n - 1, -1, -1):
  for y in range(0, n):
    print(abs(x - y), end=" ")

  print()