Pattern 241

#include <stdio.h>

int main()
{
  int n = 5;
  int i,j;

  char x = 'A';

  for(i = 1; i <= n; i++)
  {
    for(j = 1; j <= n; j++)
    {
      if ((i + j) % 2 == 1)
      {
        printf("%c ", x++);
      }
      else
      {
        printf("* ");
      }
    }
    printf("\n");
  }
  return 0;
}

#include <iostream.h>

int main()
{
  int n = 5;
  char x = 'A';

  for(int i = 1; i <= n; i++)
  {
    for(int j = 1; j <= n; j++)
    {
      if ((i + j) % 2 == 1)
      {
        cout<<x++<<" ";
      }
      else
      {
        cout<<"* ";
      }
    }
    cout<<endl;
  }
  return 0;
}

class PatternProg
{
	public static void main(String args[])
	{
	  int n = 5;
	  char x = 'A';

	  for (int i = 1; i <= n; i++)
	  {
		for (int j = 1; j <= n; j++)
		{
		  if ((i + j) % 2 == 1)
		  {
			System.out.print(x+" ");
			x++;
		  }
		  else
		  {
			System.out.print("* ");
		  }
		}
		System.out.println();
	  }
	  
	}
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;
    char x = 'A';

    for (int i = 1; i <= n; i++)
    {
      for (int j = 1; j <= n; j++)
      {
        if ((i + j) % 2 == 1)
        {
          Console.Write(x + " ");
          x++;
        }
        else
        {
          Console.Write("* ");
        }
      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

n = 5
d = 0

for x in range(1, n + 1):
  for y in range(1, n + 1):
    if (x + y) % 2 == 1:
       print(chr(d + 65) + " ", end="")
       d += 1
    else:
       print("* ", end="")
  print()