Pattern 30

#include <stdio.h>

int main()
{
  int n = 5;
  int i,j;

  char ch = 'A';

  for(i = 1; i <= n; i++)
  {
    for(j = 1; j <= n; j++)
    {
      printf("%c ", ch);

      if(ch<'Z')
        ch++;
      else
        ch='A';

      /* reset char*/
    }
    printf("\n");
  }

  return 0;
}

#include <iostream.h>

int main()
{
  int n = 5;
  

  char ch = 'A';

  for(int i = 1; i <= n; i++)
  {
    for(int j = 1; j <= n; j++)
    {
      cout<<ch<<" ";

      if(ch<'Z')
         ch++;
      else
         ch='A';

     /* reset char*/
    }
    cout<<endl;
  }

  return 0;
}

  class PatternProg
  {
  public static void main(String args[])
  {
    int n = 5;


    char ch = 'A';

    for (int i = 1; i <= n; i++)
    {
      for (int j = 1; j <= n; j++)
      {
        System.out.print(ch+" ");

        if (ch < 'Z')
        {
          ch++;
        }
        else
        {
          ch = (char)'A';
        }

        /* reset char*/
      }
      System.out.println();
    }


  }
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;


    char ch = 'A';

    for (int i = 1; i <= n; i++)
    {
      for (int j = 1; j <= n; j++)
      {
        Console.Write(ch + " ");

        /* reset char*/
        if (ch < 'Z')
        {
          ch++;
        }
        else
        {
          ch = (char)'A';
        }


      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

n = 5
ch = 0

for x in range(1, n + 1):
  for y in range(1, n + 1):
    print(chr(ch+65)+" ",end="")
    if (ch < 26):
     ch += 1
    else:
     ch = 0
  print()