Pattern 31

#include <stdio.h>

int main()
{
  int n = 5;
  int i,j;

  for(i = 0; i < n; i++)
  {
    for(j = 0; j < n; j++)
    {
      printf("%c ", i+j+65);
    }
    printf("\n");
  }

  return 0;
}

#include <iostream.h>

int main()
{
  int n = 5;
  

  for(int i = 0; i < n; i++)
  {
    for(int j = 0; j < n; j++)
    {
      cout<<(char)(i + j + 65)<<" ";
    }
    cout<<endl;
  }

  return 0;
}

  class PatternProg
  {
  public static void main(String args[])
  {
    int n = 5;


    for (int i = 0; i < n; i++)
    {
      for (int j = 0; j < n; j++)
      {
        System.out.print((char)(i + j + 65));
        System.out.print(" ");
      }
      System.out.println();
    }


  }
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;


    for (int i = 0; i < n; i++)
    {
      for (int j = 0; j < n; j++)
      {
        Console.Write((char)(i + j + 65));
        Console.Write(" ");
      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

n = 5
ch = 0

for x in range(0, n):
  for y in range(0, n):
    print(chr(x + y + 65)+" ",end="")
    if (ch < 26):
     ch += 1
    else:
     ch = 0
  print()