Pattern 243

Pattern 243 post thumbnail image

C

#include <stdio.h>

int main()
{
  int n = 5;
  int i,j;

  for(i = 1; i <= n; i++)
  {
    for(j = 1; j < 2 * n; j++)
    {
      if (j == i || j == 2 * n - i || j == n)
      {
        printf("* ");
      }
      else
      {
        printf("0 ");
      }
    }
    printf("\n");
  }
  return 0;
}

C++

#include <iostream.h>

int main()
{
  int n = 5;
  
  for(int i = 1; i <= n; i++)
  {
    for(int j = 1; j < 2 * n; j++)
    {
      if (j == i || j == 2 * n - i || j == n)
      {
        cout<<"* ";
      }
      else
      {
        cout<<"0 ";
      }
    }
    cout<<endl;
  }
  return 0;
}

Java

class PatternProg
{
	public static void main(String args[])
	{
	  int n = 5;

	  for (int i = 1; i <= n; i++)
	  {
		for (int j = 1; j < 2 * n; j++)
		{
		  if (j == i || j == 2 * n - i || j == n)
		  {
			System.out.print("* ");
		  }
		  else
		  {
			System.out.print("0 ");
		  }
		}
		System.out.println();
	  }
	  
	}
}

C#

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;

    for (int i = 1; i <= n; i++)
    {
      for (int j = 1; j < 2 * n; j++)
      {
        if (j == i || j == 2 * n - i || j == n)
        {
          Console.Write("* ");
        }
        else
        {
          Console.Write("0 ");
        }
      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

Python

n = 5

for x in range(1, n + 1):
  for y in range(1, n * 2):
    if y == x or y == 2 * n - x or y == n:
       print("* ", end="")
    else:
       print("0 ",end="")

  print()
5 1 vote
Rate this Program
Subscribe
Notify of
guest
0 Comments
Oldest
Newest Most Voted
Inline Feedbacks
View all comments

Related Patterns