Pattern 252

#include <stdio.h>

int main()
{
  int n = 5;
  int i,j;

  int x = 1;

  for(i = 1; i <= n; i++)
  {
    for(j = 1; j <= i; j++)
    {
      printf(" %2d #", x++);
    }
    printf("\n");
  }
  return 0;
}

#include <iostream.h>

int main()
{
  int n = 5;
  int x = 1;

  for(int i = 1; i <= n; i++)
  {
    for(int j = 1; j <= i; j++)
    {
      cout<<x++<<" # ";
    }
    cout<<endl;
  }
  return 0;
}

class PatternProg
{
	public static void main(String args[])
	{
	  int n = 5;
	  int x = 1;

	  for (int i = 1; i <= n; i++)
	  {
		for (int j = 1; j <= i; j++)
		{
		  System.out.printf(" %2d #", x++);
		}
		System.out.println();
	  }
	  
	}
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;
    int x = 1;

    for (int i = 1; i <= n; i++)
    {
      for (int j = 1; j <= i; j++)
      {
        Console.Write(" {0,2:D} #", x++);
      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

n = 5
d = 1

for x in range(1, n + 1):
  for y in range(1, x + 1):
    print(" {:2d} #".format(d), end="")
    d += 1
  print()