Pattern 283

Pattern 283 post thumbnail image

C

#include <stdio.h>
int main()
{
  int i,j;
  int n=5;

  for(i=n; i>=1; i--)
  {
    for(j=n; j>=1; j--)
    {
      if(i>=j)
      {
        if(i%2==0)
          printf("*");
        else
          printf("%d",j);
      }
      else
      {
        printf(" ");
      }

    }
    printf("\n");
  }
  return 0;
}

C++

#include <stdio.h>
int main()
{
  int i,j;
  int n=5;

  for(i=n; i>=1; i--)
  {
    for(j=n; j>=1; j--)
    {
      if(i>=j)
      {
        if(i%2==0)
          printf("*");
        else
          printf("%d",j);
      }
      else
      {
        printf(" ");
      }

    }
    printf("\n");
  }
  return 0;
}

Java

class PatternProg
{
	public static void main(String args[])
	{

		int n = 5;

		for (int i = n;i >= 1;i--)
		{
		 for (int j = n;j >= 1;j--)
		 {
		   if (i >= j)
		   {
				if (i % 2 == 0)
				{
			   System.out.print("*");
				}
			  else
			  {
			   System.out.print(j);
			  }
		   }
		   else
		   {
			System.out.print(" ");
		   }

		 }
		  System.out.println();
		}
		
	}
}

C#

using System;

class PatternProg
{
  public static void Main()
  {

    int n = 5;

    for (int i = n; i >= 1; i--)
    {
      for (int j = n; j >= 1; j--)
      {
        if (i >= j)
        {
          if (i % 2 == 0)
          {
            Console.Write("*");
          }
          else
          {
            Console.Write(j);
          }
        }
        else
        {
          Console.Write(" ");
        }

      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

Python

n = 5

for x in range(n, 0, -1):
  for y in range(n, 0, -1):
      if x >= y:
         if x % 2 == 0:
            print("*", end="")
         else:
            print(y,end="")
      else:
         print(" ", end="")
  print()
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