Pattern 285

Pattern 285 post thumbnail image

C

#include <stdio.h>
int main()
{
  int i,j;
  int n=5;

  for(i=n; i>=1; i--)
  {
    for(j=1; j<=n; j++)
    {
      if(i<=j)
      {
        if(i%2==0)
          printf("* "); // space after *
        else
          printf("# "); // space after #
      }
      else
      {
        printf(" ");
      }

    }
    printf("\n");
  }
  return 0;
}

C++

#include <iostream.h>
int main()
{
	
	int n=5;
	
	for(int i =n;i>=1;i--)
    {
     for(int j =1;j<=n;j++)
      {
       if(i<=j)
       {
		    if(i%2==0)
	        cout<<"* "; // space after *           
        else
          cout<<"# "; // space after #          
       }
       else
       {
       	cout<<" ";           
       }
       
      }
      cout<<endl;           
    }
	return 0;
}

Java

class PatternProg
{
	public static void main(String args[])
	{

		int n = 5;

		for (int i = n;i >= 1;i--)
		{
		 for (int j = 1;j <= n;j++)
		 {
		   if (i <= j)
		   {
				if (i % 2 == 0)
				{
				System.out.print("* ");
				}
			else
			{
			  System.out.print("# ");
			}
		   }
		   else
		   {
			   System.out.print(" ");
		   }

		 }
		  System.out.println();
		}
		
	}
}

C#

using System;

class PatternProg
{
  public static void Main()
  {

    int n = 5;

    for (int i = n; i >= 1; i--)
    {
      for (int j = 1; j <= n; j++)
      {
        if (i <= j)
        {
          if (i % 2 == 0)
          {
            Console.Write("* ");
          }
          else
          {
            Console.Write("# ");
          }
        }
        else
        {
          Console.Write(" ");
        }

      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

Python

n = 5

for x in range(n, 0, -1):
  for y in range(1, n + 1):
      if x <= y:
         if x % 2 == 0:
            print("* ", end="")
         else:
            print("# ", end="")
      else:
        print(" ", end="")
  print()
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