Pattern 365

#include <stdio.h>

int main()
{
  int n = 7;
  int i,j;

  for(i=1; i <= n; i++)
  {
    for(j=1; j <= n; j++)
    {
      if (j == i || j == n || i == 1)
      {
        printf("* "); // space after *
      }
      else
      {
        printf("  "); // 2ws
      }
    }
    printf("\n");
  }
  return 0;
}

#include <iostream.h>

int main()
{
   int n = 7;
   
   
   for(int i =1; i <= n; i++)
   {
     for(int j =1; j <= n; j++)
     {
      if (j == i || j == n || i == 1)
      {
        cout<<"* "; // space after *
      }        
      else
      {
        cout<<"  "; // 2ws
      }                    
    }
    cout<<endl;
  }
    return 0;
}

class PatternProg
{
	public static void main(String args[])
	{
	   int n = 7;


	   for (int i = 1; i <= n; i++)
	   {
		 for (int j = 1; j <= n; j++)
		 {
		  if (j == i || j == n || i == 1)
		  {
			System.out.print("* ");
		  }
		  else
		  {
			System.out.print("  "); //2ws
		  }
		 }
		System.out.println();
	   }
		
	}
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 7;


    for (int i = 1; i <= n; i++)
    {
      for (int j = 1; j <= n; j++)
      {
        if (j == i || j == n || i == 1)
        {
          Console.Write("* ");
        }
        else
        {
          Console.Write("  "); //2ws
        }
      }
      Console.WriteLine();
    }

    Console.ReadKey(true);

  }
}

n = 7
for x in range(1, n + 1):
  for y in range(1, n + 1):
    if y == x or y == n or x == 1:
       print("* ", end="")
    else:
       print("  ", end="")  # 2ws
  print()