Pattern 52

#include <stdio.h>

int main()
{
  int n = 5;
  int i,j;
  int x=n,y,t;

  for(i = n; i >= 1; i--)
  {
    t = x;
    y = i + 1;
    for (j = n; j >= i; j--)
    {
      printf("%2d ", t);
      t = t - y;
      y++;
    }
    x = x + i - 1;
    printf("\n");
  }
  return 0;
}

#include <iostream.h>

int main()
{
  int n = 5;
  
  int x=n,y,t;

  for(int i = n; i >= 1; i--)
  {
    t = x;
    y = i + 1;
    for(int j = n; j >= i; j--)
    {
      cout<<t<<" ";
      t = t - y;
      y++;
    }
    x = x + i - 1;
    cout<<endl;
  }
  return 0;
}

  class PatternProg
  {
	public static void main(String args[])
	{
	  int n = 5;

	  int x = n;
	  int y;
	  int t;

	  for (int i = n; i >= 1; i--)
	  {
		t = x;
		y = i + 1;
		for (int j = n; j >= i; j--)
		{
		  System.out.printf("%2d ",t);
		  t = t - y;
		  y++;
		}
		x = x + i - 1;
		System.out.println();
	  }
	  
	}
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;

    int x = n;
    int y;
    int t;

    for (int i = n; i >= 1; i--)
    {
      t = x;
      y = i + 1;
      for (int j = n; j >= i; j--)
      {
        Console.Write("{0,2:D} ", t);
        t = t - y;
        y++;
      }
      x = x + i - 1;
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

n = 5
d = n
for x in range(n, 0, -1):
  t = d
  e = x + 1
  for y in range(n, x - 1, -1):
    print("{:2d} ".format(t), end="")
    t = t - e
    e += 1

  d = d + x - 1
  print()