Pattern 102

Pattern 102 post thumbnail image

C

#include <stdio.h>

int main()
{
  int n = 5, x = 1;
  int i,j;

  for(i = n; i >= 1; i--)
  {
    for (j = 1; j <= n; j++)
    {
      if(i<=j)
      {
        printf("%2d ", x);
        x+=2;
      }
      else
      {
        printf("   "); //3ws
      }

    }
    printf("\n");
  }
  return 0;
}

C++

#include <iostream.h>
#include <iomanip.h>

int main()
{
  int n = 5, x = 1;
  

  for(int i = n; i >= 1; i--)
  {
     for(int j = 1; j <= n; j++)
    {
      if(i<=j)
      {
       
	   cout<<setw(3)<<x;
       x+=2;
    }
    else
    {
      cout<<setw(3)<<" ";
    }
    
  }
    cout<<endl;
  }
  return 0;
}

Java

class PatternProg
{
	public static void main(String args[])
	{
	  int n = 5;
	  int x = 1;


	  for (int i = n; i >= 1; i--)
	  {
		 for (int j = 1; j <= n; j++)
		 {
		  if (i <= j)
		  {

		   System.out.printf("%3d", x);
		   x += 2;
		  }
		else
		{
		  System.out.printf("   "); // 3ws
		}

		 }
		System.out.println();
	  }
	  
	}
}

C#

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;
    int x = 1;


    for (int i = n; i >= 1; i--)
    {
      for (int j = 1; j <= n; j++)
      {
        if (i <= j)
        {

          Console.Write("{0,3:D}", x);
          x += 2;
        }
        else
        {
          Console.Write("   "); // 3ws
        }

      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

Python

n = 5
d = 1

for x in range(n, 0, -1):
  for y in range(1, n + 1):
    if x <= y:
       print("{:3d}".format(d), end="")
       d += 2
    else:
       print("   ", end="")  # 3ws
  print()
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