Pattern 103

Pattern 103 post thumbnail image

C

#include <stdio.h>

int main()
{
  int n = 5;
  int i,j,s;

  for(i = 1; i <= n; i++)
  {
    for(s = n - 1; s>=i; s--)
    {
      printf("   "); // 3ws
    }

    for (j = 1; j <= i; j++)
    {
      printf("%2d ", i * j);
    }
    printf("\n");
  }
  return 0;
}

C++

#include <iostream.h>
#include <iomanip.h>

int main()
{
  int n = 5;
  

  for(int i = 1; i <= n; i++)
  {
    for(int s = n - 1; s>=i; s--)
    {
      cout<<setw(3)<<" ";
    }

    for(int j = 1; j <= i; j++)
    {
      cout<<setw(3)<<(i * j);
    }
    cout<<endl;
  }
  return 0;
}

Java

class PatternProg
{
	public static void main(String args[])
	{
	  int n = 5;


	  for (int i = 1; i <= n; i++)
	  {
		for (int s = n - 1; s >= i; s--)
		{
		  System.out.print("   "); //3ws
		}

		for (int j = 1; j <= i; j++)
		{
		  System.out.printf("%3d", (i * j));
		}
		System.out.println();
	  }
	  
	}
}

C#

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;


    for (int i = 1; i <= n; i++)
    {
      for (int s = n - 1; s >= i; s--)
      {
        Console.Write("   "); //3ws
      }

      for (int j = 1; j <= i; j++)
      {
        Console.Write("{0,3:D}", (i * j));
      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

Python

n = 5

for x in range(1, n + 1):
    for s in range(n - 1, x - 1, -1):
        print("   ", end="")  # 3ws
    for y in range(1, x + 1):
        print("{:3d}".format(x * y), end="")
    print()
0 0 votes
Rate this Program
Subscribe
Notify of
guest
0 Comments
Oldest
Newest Most Voted
Inline Feedbacks
View all comments

Related Patterns