Pattern 138

C

#include <stdio.h>
#include <conio.h>
int main()
{
  int i,j,k;

  for(i=4; i>=0; i--)
  {
    for(k=3; k>=i; k--)
    {
      printf(" ");
    }
    for(j=i; j>=0; j--)
    {
      printf("%c ",(i-j)+65); // 65 is ASCII of 'A'
    }
    printf("\n");
  }
  return 0;
}

C++

 #include<iostream.h>
 
 int main()
 {
 int i,j,k;
 
 for(int i =4; i>=0; i--)
 {
  for(int k =3; k>=i; k--)
  {
   cout<<" ";
  }
  for(int j =i; j>=0; j--)
  {
   cout<<char((i-j)+65)<<" "; // 65 is ASCII of 'A'
  }
  cout<<endl;
 }
  return 0;
 }

Java

   class PatternProg
   {
     public static void main(String args[])
     {
     int i;
     int j;
     int k;
      
     for (i = 4; i >= 0; i--)
     {
      for (k = 3; k >= i; k--)
      {
       System.out.print(" ");
      }
      for (j = i; j >= 0; j--)
      {
       System.out.print((char)((i - j) + 65));
       System.out.print(" ");
      }
      System.out.print("\n");
     }
       
     }
 }

C#

using System;

class PatternProg
{
  public static void Main()
  {
    int i;
    int j;
    int k;

    for (i = 4; i >= 0; i--)
    {
      for (k = 3; k >= i; k--)
      {
        Console.Write(" ");
      }
      for (j = i; j >= 0; j--)
      {
        Console.Write((char)((i - j) + 65) + " ");
      }
      Console.WriteLine();
    }
    Console.ReadKey(true);
  }
}

Python

for x in range(5, 0, -1):
    for y in range(x, 5):
        print(" ", end="")
    for z in range(0, x):
        print(chr(z + 65) + " ", end="")
    print()