#include <stdio.h>
int main()
{
int n = 5;
int i,j;
for(i = 1; i <= n; i++)
{
for (j = 1; j <= n; j++)
{
if (i == 1 || i == n || j == 1 || j == n)
printf("1 ");
else
printf("0 ");
}
printf("\n");
}
return 0;
}
#include <iostream.h>
int main()
{
int n = 5;
for(int i = 1; i <= n; i++)
{
for(int j = 1; j <= n; j++)
{
if (i == 1 || i == n || j == 1 || j == n)
cout<<"1 ";
else
cout<<"0 ";
}
cout<<endl;
}
return 0;
}
class PatternProg
{
public static void main(String args[])
{
int n = 5;
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= n; j++)
{
if (i == 1 || i == n || j == 1 || j == n)
{
System.out.print("1 ");
}
else
{
System.out.print("0 ");
}
}
System.out.println();
}
}
}
using System;
class PatternProg
{
public static void Main()
{
int n = 5;
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= n; j++)
{
if (i == 1 || i == n || j == 1 || j == n)
{
Console.Write("1 ");
}
else
{
Console.Write("0 ");
}
}
Console.WriteLine();
}
Console.ReadKey(true);
}
}
n = 5
for x in range(1, n + 1):
for y in range(1, n + 1):
if x == 1 or x == n or y == 1 or y == n:
print("1 ", end="")
else:
print("0 ", end="")
print()