Pattern 174

#include <stdio.h>

int main()
{
  int n = 9, px = 1;
  int y = 1;
  int i,j;

  for(i = 1; i <= n; i++)
  {
    for (j = 1; j <= px; j++)
    {
      printf("%2d ", y++);
    }
    if (i <= n / 2)
      px++;
    else
      px--;
    printf("\n");
  }
  return 0;
}

#include <iostream.h>

int main()
{
  int n = 9, px = 1;
  int y = 1;
  
  
  for(int i = 1; i <= n; i++)
  {
    for(int j = 1; j <= px; j++)
    {
      cout<<y++<<" ";
    }
    if (i <= n / 2)
      px++;
    else
      px--;
    cout<<endl;
  }
  return 0;
}

class PatternProg
{
	public static void main(String args[])
	{
	  int n = 9;
	  int px = 1;
	  int y = 1;


	  for (int i = 1; i <= n; i++)
	  {
		for (int j = 1; j <= px; j++)
		{
		  System.out.print(y+" ");
		  y++;
		}
		if (i <= n / 2)
		{
		  px++;
		}
		else
		{
		  px--;
		}
		System.out.println();
	  }
	  
	}
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 9;
    int px = 1;
    int y = 1;


    for (int i = 1; i <= n; i++)
    {
      for (int j = 1; j <= px; j++)
      {
        Console.Write(y + " ");
        y++;
      }
      if (i <= n / 2)
      {
        px++;
      }
      else
      {
        px--;
      }
      Console.WriteLine();
    }

    Console.ReadKey(true);
  }
}

n = 9
px = 1
e = 1

for x in range(1, n + 1):
  for y in range(1, px + 1):
    print(e, end=" ")
    e += 1

  if x <= n // 2:
     px += 1
  else:
     px -= 1
  print()