Pattern 220

#include <stdio.h>
int main()
{
  int i,j;
  int n=5;
  for (i=1; i<=n; i++)
  {
    for (j=n; j>=1; j--)
    {
      if (j>i)
        printf("*");
      else
        printf("%d",j);
    }
    printf("\n");
  }
  return 0;
}

#include <iostream.h>
int main()
{
    int i,j;
    int n=5;
    for (i=1; i<=n; i++)
    {
        for (j=n; j>=1; j--)
        {
            if (j>i)
                cout<<"*";
            else
                cout<<j;
        }
        cout<<endl;
    }
    return 0;
}

class PatternProg
{
    public static void main(String args[])
    {
        int n = 5;
        for (int i = 1; i <= n; i++)
        {
            for (int j = n; j >= 1; j--)
            {
                if (j > i)
                {
                    System.out.print("*");
                }
                else
                {
                    System.out.print(j);
                }
            }
            System.out.println();
        }
    }
}

using System;

class PatternProg
{
  public static void Main()
  {
    int n = 5;
    for (int i = 1; i <= n; i++)
    {
      for (int j = n; j >= 1; j--)
      {
        if (j > i)
        {
          Console.Write("*");
        }
        else
        {
          Console.Write(j);
        }
      }
      Console.WriteLine();
    }
    Console.ReadKey(true);
  }
}

n = 5
for x in range(1, n + 1):
    for y in range(n, 0, -1):
      if y > x:
        print("*", end="")
      else:
        print(y, end="")
    print()